Optimal. Leaf size=132 \[ \frac {18 e^3 (e \cos (c+d x))^{5/2}}{5 a^3 d}+\frac {6 e^6 \sqrt {\cos (c+d x)} F\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{a^3 d \sqrt {e \cos (c+d x)}}+\frac {6 e^5 \sqrt {e \cos (c+d x)} \sin (c+d x)}{a^3 d}+\frac {4 e (e \cos (c+d x))^{9/2}}{a d (a+a \sin (c+d x))^2} \]
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Rubi [A]
time = 0.11, antiderivative size = 132, normalized size of antiderivative = 1.00, number of steps
used = 5, number of rules used = 5, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {2759, 2761,
2715, 2721, 2720} \begin {gather*} \frac {6 e^6 \sqrt {\cos (c+d x)} F\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{a^3 d \sqrt {e \cos (c+d x)}}+\frac {6 e^5 \sin (c+d x) \sqrt {e \cos (c+d x)}}{a^3 d}+\frac {18 e^3 (e \cos (c+d x))^{5/2}}{5 a^3 d}+\frac {4 e (e \cos (c+d x))^{9/2}}{a d (a \sin (c+d x)+a)^2} \end {gather*}
Antiderivative was successfully verified.
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Rule 2715
Rule 2720
Rule 2721
Rule 2759
Rule 2761
Rubi steps
\begin {align*} \int \frac {(e \cos (c+d x))^{11/2}}{(a+a \sin (c+d x))^3} \, dx &=\frac {4 e (e \cos (c+d x))^{9/2}}{a d (a+a \sin (c+d x))^2}+\frac {\left (9 e^2\right ) \int \frac {(e \cos (c+d x))^{7/2}}{a+a \sin (c+d x)} \, dx}{a^2}\\ &=\frac {18 e^3 (e \cos (c+d x))^{5/2}}{5 a^3 d}+\frac {4 e (e \cos (c+d x))^{9/2}}{a d (a+a \sin (c+d x))^2}+\frac {\left (9 e^4\right ) \int (e \cos (c+d x))^{3/2} \, dx}{a^3}\\ &=\frac {18 e^3 (e \cos (c+d x))^{5/2}}{5 a^3 d}+\frac {6 e^5 \sqrt {e \cos (c+d x)} \sin (c+d x)}{a^3 d}+\frac {4 e (e \cos (c+d x))^{9/2}}{a d (a+a \sin (c+d x))^2}+\frac {\left (3 e^6\right ) \int \frac {1}{\sqrt {e \cos (c+d x)}} \, dx}{a^3}\\ &=\frac {18 e^3 (e \cos (c+d x))^{5/2}}{5 a^3 d}+\frac {6 e^5 \sqrt {e \cos (c+d x)} \sin (c+d x)}{a^3 d}+\frac {4 e (e \cos (c+d x))^{9/2}}{a d (a+a \sin (c+d x))^2}+\frac {\left (3 e^6 \sqrt {\cos (c+d x)}\right ) \int \frac {1}{\sqrt {\cos (c+d x)}} \, dx}{a^3 \sqrt {e \cos (c+d x)}}\\ &=\frac {18 e^3 (e \cos (c+d x))^{5/2}}{5 a^3 d}+\frac {6 e^6 \sqrt {\cos (c+d x)} F\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{a^3 d \sqrt {e \cos (c+d x)}}+\frac {6 e^5 \sqrt {e \cos (c+d x)} \sin (c+d x)}{a^3 d}+\frac {4 e (e \cos (c+d x))^{9/2}}{a d (a+a \sin (c+d x))^2}\\ \end {align*}
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Mathematica [C] Result contains higher order function than in optimal. Order 5 vs. order 4 in
optimal.
time = 0.14, size = 66, normalized size = 0.50 \begin {gather*} -\frac {2 \sqrt [4]{2} (e \cos (c+d x))^{13/2} \, _2F_1\left (\frac {3}{4},\frac {13}{4};\frac {17}{4};\frac {1}{2} (1-\sin (c+d x))\right )}{13 a^3 d e (1+\sin (c+d x))^{13/4}} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 2.62, size = 181, normalized size = 1.37
method | result | size |
default | \(-\frac {2 e^{6} \left (-8 \left (\sin ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-20 \left (\sin ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \cos \left (\frac {d x}{2}+\frac {c}{2}\right )+12 \left (\sin ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+15 \sqrt {\frac {1}{2}-\frac {\cos \left (d x +c \right )}{2}}\, \sqrt {2 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-1}\, \EllipticF \left (\cos \left (\frac {d x}{2}+\frac {c}{2}\right ), \sqrt {2}\right )+10 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) \cos \left (\frac {d x}{2}+\frac {c}{2}\right )+34 \left (\sin ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-19 \sin \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{5 a^{3} \sin \left (\frac {d x}{2}+\frac {c}{2}\right ) \sqrt {-2 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) e +e}\, d}\) | \(181\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [C] Result contains higher order function than in optimal. Order 9 vs. order
4.
time = 0.10, size = 95, normalized size = 0.72 \begin {gather*} \frac {-15 i \, \sqrt {2} e^{\frac {11}{2}} {\rm weierstrassPInverse}\left (-4, 0, \cos \left (d x + c\right ) + i \, \sin \left (d x + c\right )\right ) + 15 i \, \sqrt {2} e^{\frac {11}{2}} {\rm weierstrassPInverse}\left (-4, 0, \cos \left (d x + c\right ) - i \, \sin \left (d x + c\right )\right ) - 2 \, {\left (\cos \left (d x + c\right )^{2} e^{\frac {11}{2}} + 5 \, e^{\frac {11}{2}} \sin \left (d x + c\right ) - 20 \, e^{\frac {11}{2}}\right )} \sqrt {\cos \left (d x + c\right )}}{5 \, a^{3} d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {{\left (e\,\cos \left (c+d\,x\right )\right )}^{11/2}}{{\left (a+a\,\sin \left (c+d\,x\right )\right )}^3} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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